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Ventilation calculations for open-flued gas appliances under BS 5440-2

How to calculate the required permanent ventilation free area for domestic open-flued appliances.

Open-flued gas appliances draw air for combustion from the room in which they are installed. To ensure safe, clean combustion and prevent carbon monoxide release, a permanent ventilation opening to the outside air must be provided under BS 5440-2:

Sizing Rules for Appliances in Rooms

For open-flued appliances (such as boilers or water heaters) installed in a room (not a compartment):

  • First 7 kW of Net Heat Input: Requires no ventilation (0 cm² free area).
  • Each kW above 7 kW: Requires 5 cm² of free area per kW.

Sizing Formula

$$\text{Required Ventilation Free Area} = (\text{Net Input in kW} - 7) \times 5 \text{ cm}^2$$

Example Calculation

A boiler has a net heat input of 18 kW installed in a domestic utility room:

  1. Deduct the first 7 kW: $18\text{ kW} - 7\text{ kW} = 11\text{ kW}$.
  2. Multiply the remaining input by 5: $11 \times 5\text{ cm}^2 = 55\text{ cm}^2$.
  3. The required permanent opening to outside air is 55 cm² of free area.

Key Installation Guidelines

  • Permanent Openings: Vents must not be closable or adjustable by the user.
  • Grille Material: Grilles must have a mesh size of at least 6 mm (or flyscreen removed) to prevent dust/insects blocking the air flow.
  • Vent Position: Vents should be positioned where they cannot be easily blocked or cause cold draughts that tempt users to seal them.

*Original revision guidance; confirm standard calculations against BS 5440-2.*